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=176-16H^2
We move all terms to the left:
-(176-16H^2)=0
We get rid of parentheses
16H^2-176=0
a = 16; b = 0; c = -176;
Δ = b2-4ac
Δ = 02-4·16·(-176)
Δ = 11264
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$H_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$H_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{11264}=\sqrt{1024*11}=\sqrt{1024}*\sqrt{11}=32\sqrt{11}$$H_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-32\sqrt{11}}{2*16}=\frac{0-32\sqrt{11}}{32} =-\frac{32\sqrt{11}}{32} =-\sqrt{11} $$H_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+32\sqrt{11}}{2*16}=\frac{0+32\sqrt{11}}{32} =\frac{32\sqrt{11}}{32} =\sqrt{11} $
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